返回首页

返回算法分类分析

第一题 Clone Graph

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.

OJ's undirected graph serialization: Nodes are labeled uniquely.

We use # as a separator for each node, and , as a separator for node label and each neighbor of the node. As an example, consider the serialized graph {0,1,2#1,2#2,2}.

The graph has a total of three nodes, and therefore contains three parts as separated by #.

  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle. Visually, the graph looks like the following:

       1
      / \
     /   \
    0 --- 2
         / \
         \_/

解法

# Definition for a undirected graph node
# class UndirectedGraphNode:
#     def __init__(self, x):
#         self.label = x
#         self.neighbors = []

class Solution:
# @param node, a undirected graph node
# @return a undirected graph node

def __init__(self):
    self.dict = {}

def cloneGraph(self, node):
    # write your code here
    if node is None:
        return node

    if node.label not in self.dict:
        # if the node is not in dict, create the copy in dict first
        n1 = UndirectedGraphNode(node.label)
        self.dict[node.label] = n1

        # append all the neighbors by using depth first search. It creates 
        # all the nodes first
        neighbors = []
        for i in node.neighbors:
            neighbors.append(self.cloneGraph(i))
        n1.neighbors = neighbors
        return n1
    else:
        return self.dict[node.label]